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## Smithing Mithril Bars at BF Edit

$470 coins* \frac{1 M}{10^6 coins} = 4.70*10^{-4} M$ Scientific notation and significant figures aren't really needed nor is converting to millions.

$40.000 M * \frac{1 ore}{4.70*10^{-4} M} \approx$ 85,106 $ore$

• Thus, 85,106 Mithril ore and 170,212 coal are needed to produce $85,106$ Mithril bars with the Blast Furnace.

### Profit off Mithril Bolts Edit

$510 coins* \frac{1 M}{10^6 coins} = 5.10*10^{-4} M$ Scientific notation and significant figures aren't really needed nor is converting to millions.

$40.000 M * \frac{1 ore}{5.10*10^{-4} M} \approx$ 78,431 $ore$

• Thus, 78,431 feathers, 78,431 Mithril ore, and 156,862 coal are needed to produce $784,310$ Mithril bolts worth 100 coins each.
• Profit: 78,431,000

## Determining Cost Efficiency Edit

### Formula Edit

• Use $d = \frac{ac}{b}$ for determining the best item to use for spending the least amount of money.
• $a$ is the experience that the pricier item grants.
• $b$ is the amount of XP the cheaper item gives.
• $c$ is said item's (the cheaper item's) cost.
• $d$ determines the cost that the higher-priced item should be to make it worth using.
• If, however, $d$ exceeds the cost of item $a$ (the higher-priced item), then use $d > \frac{ac}{b}$, so item $a$ is better to use. Otherwise, $d < \frac{ac}{b}$ makes item $b$ (the lower-priced item) better!

### Problem Edit

Metal wishes to achieve 99 Prayer for a Skillcape. He noticed that dragon bones are 2,000 coins each, and lava dragon bones are 2,100 coins each. When used on a fully-lit gilded altar, each item grants 252 experience and 297.5 experience respectively. Which of the two would be better to use price-wise?

• Let $a = 297.5$
• Let $b = 252$, and $c = 2000$
• So, we now have $\frac{297.5*2000}{252} = d$
• And, we get $d=$ 2361.1111111111, which is about 2361, thus making the expression $d \approx 2361.$
• Since $d > 2100$, use item $a$, which is lava dragon bones.
• In order to make dragon bones work, the following has to occur.

$\frac{297.5c}{252} = 2100$

$\frac{252}{297.5} \left(\frac{297.5c}{252}\right) = 2100 \left(\frac{252}{297.5}\right)$

$c = 2100 \left(\frac{252}{297.5}\right) \approx 1778.82$

• So, $c \approx 1778$ in order for dragon bones to be feasible.

### Checking Answer Edit

• $\frac{a}{b} = \frac{d}{c}$

• So, $\frac{297.5}{252} = \frac{2361.1111111111}{2000}$, which is 1.1805555555556 = 1.1805555555556.

### Final Answer Edit

Lava dragon bones would be better to use since dragon bones are worth more than 2,361 coins.

Alternatively, this can be figured out by taking the two and seeing how much each would cost from your current level to 99. From level 70, it's 48,797 dragon bones, which cost 97,594,000 coins compared to using 41,334 lava dragon bones costing only 86,801,400.

### Elusive Drops Edit

Below is a table of some of the rarest and most sought-after drops in Old School RuneScape. Also, the kill count or number of kills required is based on a 90% probability of getting the drop.

1. 1.0 1.1 1/250 from chewed bones (and 574 bones for 90% chance)
2. 2.0 2.1 1/2,000 from Thermonuclear smoke devil (and 4,604 kills for 90% chance)
3. 3.0 3.1 1/128 from Kalphite Queen (and 294 kills for 90% chance)
4. 4.0 4.1 1/10,000 from Ancient Wyvern (and 23,025 kills for 90% chance)
5. 5.0 5.1 1/5,000 from King Black Dragon (and 11,512 kills for 90% chance)
6. 6.0 6.1 1/1,500 from King Black Dragon only (3,453 kills for 90% chance) and 1/256 from other Wilderness bosses (588 kills for 90% chance)

## Farming Herbs Edit

Below is a table depicting profitability in farming some herbs. Profit is assumed by harvesting and cleaning six herbs. Along with the price of the seed, Ultracompost (743) is deducted as cost.

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